√(4√2-7)²+4√2
Объяснение. √(4√2–7)²+4√2= ( т.к (4√2–7)²=(7-4√2)²) = =√(7-4√2)²+4√2= =|7-4√2|+4√2= ( т.к. 7-4√2=√49-√32>0 , то |7-4√2|=7-4√2 )= =7-4√2+4√2=7