[b]y=kx[/b]
π/3=k*(π/6)
[b]k=2[/b]
y=[green]2x[/green]
dy=[blue]2dx[/blue]
= ∫ ^(π/6)_(0) (cosx-[green]2x[/green])dx+(x+tg[green]2x[/green])[blue]2dx[/blue]=
определенный интеграл
=[b]2[/b]*∫ ^(π/6)_(0) (cosx-2x+x+tg2x)dx=
=[b]2[/b]*(sinx-(x^2/2)-(1/2)ln|cos2x|)|^(π/6)_(0)=...