Решите пожалуйста №8.089
tg(π/10)-ctg(π/10)=(sin(π/10)/cos(π/10))-(cos(π/10)/sin(π/10)= =(sin^2(π/10)-cos^2(π/10))/(sin(π/10)·cos(π/10))= =-cos(2π/10)/(sin(π/10)·cos(π/10))= =-2cos(π/5)/(2sin(π/10)·cos(π/10))= =-2cos(π/5)/(sin(2π/10)) -2ctg(π/5) -2ctg(π/5)/ctg^2(π/5)=-2/ctg(π/5)