Сократить дробь [block](24^(n+3))/(2^(3n+5)*3^(n+2))[/block]
[m]\frac{24^{n+3}}{2^{3n+5}\cdot 3^{n+2}}=\frac{(3\cdot 2^3)^{n+3}}{2^{3n+5}\cdot 3^{n+2}}=\frac{3^{n+3}\cdot 2^{3n+9}}{2^{3n+5}\cdot 3^{n+2}}=3^{n+3-(n+2)}\cdot 2^{3n+9-3n-5}=3\cdot 2^4=3\cdot 16=48[/m]
