Задача 50596 ...

sova

2020-05-18 13:23:12

[m] ∫ \frac{4}{(x-\frac{1}{2})^3}dx=4\cdot ∫ (x-\frac{1}{2})^{-3}d(x-\frac{1}{2})=[/m] формула ∫ u^(-3)du=

[m]=4\cdot \frac{(x-\frac{1}{2})^{-3+1}}{-3+1}+C=-2\frac{1}{(x-\frac{1}{2})^2}+C[/m]