[m]u=arcsinx[/m]
[m]dv=dx[/m]
[m]du=\frac{1}{\sqrt{1-x^2}}dx[/m]
[m]v=x[/m]
[m] ∫ arcsinx dx=x\cdot arcsinx- ∫ x\cdot \frac{1}{\sqrt{1-x^2}}dx=[/m]
[m]=x\cdot arcsinx- (-\frac{1}{2}) \frac{(-2x)}{\sqrt{1-x^2}}dx=[/m]
[m]=x\cdot arcsinx+(\frac{1}{2})\cdot 2\sqrt{1-x^2}+C=[/m]
[m]=x\cdot arcsinx+\sqrt{1-x^2}+C=[/m]