Вычислить,варианты ответа 1 -1/8 2
log_(4)sin(π/4)=log_(4)1/sqrt(2)=log_(2^2)2^(-1/2)=-(1/4)log_(2)2=-(1/4) log_(3)tg(π/6)=log_(3)1/sqrt(3)=log_(3)3^(-1/2)=-(1/2)log_(3)3=(-1/2) [blue]log_(4)sin(π/4)-log_(3)tg(π/6)[/blue]=(-1/4)-(-1/2)=[blue]1/4[/blue] 16^([blue]1/4[/blue])=(2^(4))^([blue]1/4[/blue])=2 О т в е т. [b]2[/b]