2. A(3; 5; –2) B (5; –1; 1) AC = CB; C ∈ OX Найти: координаты C.
C(c;0;0) AC2=(c–3)2+(0–5)2+(–2–0)2 CB2=(5–c)2+(–1–0)2+(1–0)2 (c–3)2+(0–5)2+(–2–0)2=(5–c)2+(–1–0)2+(1–0)2 раскрываем скобки. решаем уравнение и находим с