Задача 31860 ...

madon00

2018-12-12 13:02:16

∫cos^3x dx

sova

2018-12-12 13:05:11

∫ сos^3xdx= ∫ (cos^2x)*cosxdx= ∫ (1-sin^2x)*cosxdx=


замена

sinx=t
cosxdx=dt

= ∫ (1-t^2)dt= t-(t^3/3) + C =

=sinx - (1/3)sin^3x+C