Решить уравнение log5 25/x+log5 sqrt(5x) = 2
ОДЗ: х>0. log(5)(25/x)=log(5)25-log(5)x=2-log(5)x; log(5)√(5x)=log(5)√5+log(5)√x=(1/2)+(1/2)*log(5)x;log[5]25/x+log[5]√(5x)=2-log(5)x+(1/2)+(1/2)*log(5)x=2,5-0,5*log(5)x; 2,5-0,5*log(5)x=2; -0,5*log(5)x=-0,5; log(5)x=1; x=5. О т в е т. х=5.