Задача 3214 4 в степени log2 5 + 2log(0,25) 3...

SvetlanaSinickaya

21.05.2015

4 в степени log2 5 + 2log(0,25) 3

slava191

06.08.2015

4^(log2 5 + 2log(0.25) 3) =

2^(2log2 5^2 + 2*(-1/2)log2 3^2) =

2^(log2 25 + 2*(-1/2)log2 9) =
2^(log2 25 - log2 9) =
2^(log2 (25/9)) = 25/9