sin3x+sin4x=2
{sin3x=1 {sin4x=1 {3x=(π/2)+2πk, k∈Z {4x=(π/2)+2πn, n∈Z {x=(π/6)+(2π/3)*k, k∈Z {x=(π/8)+(2π/4)*n, n∈Z (π/6)+(2π/3)*k=(π/8)+(2π/4)*n, n=(1/12)+(16/12)k